Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.2 Sequences - 8.2 Exercises - Page 616: 8

Answer

$a_n=\begin{cases} n+1,n\in\{1,2,3,4,5,6,7,8,9,10\} \\ \dfrac{3}{n},n>10 \end{cases}$ $b_n=\begin{cases} n-1,n\in\{1,2,3,4,5,6,7,8,9,10\}\\ \dfrac{3}{n},n>10 \end{cases}$

Work Step by Step

Consider the sequences: $a_n=\begin{cases} n+1,n\in\{1,2,3,4,5,6,7,8,9,10\}\\ \dfrac{3}{n},n>10 \end{cases}$ $b_n=\begin{cases} n-1,n\in\{1,2,3,4,5,6,7,8,9,10\}\\ \dfrac{3}{n},n>10 \end{cases}$ The two sequences have only the first 10 terms different, but have the same limit 0.
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