Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.2 Sequences - 8.2 Exercises - Page 616: 51

Answer

Oscillates and diverges.

Work Step by Step

The general form of geometric series is written as: $\Sigma_{n=0}^{\infty} ar^n=a+ar+ar^2+ar^3+.......=\dfrac{a}{1-r}~~~~(1)$ when $|r| \lt 1$, then the sequence converges. Here, we are given the geometric series $(-2.5)^{n}$ On comparing the above equation with the equation (1), we get $a=1$ and $r=-2.5$ This implies that the common ratio $|r|=|-2.5| \gt 1$ , so the sequence diverges. Hence, we conclude that the sequence increase and decrease and the every term of the sequence shows an alternate pattern. This means that the given sequence oscillates and diverges.
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