Calculus: Early Transcendentals (2nd Edition)

Published by Pearson
ISBN 10: 0321947347
ISBN 13: 978-0-32194-734-5

Chapter 8 - Sequences and Infinite Series - 8.2 Sequences - 8.2 Exercises: 17

Answer

$\lim\limits_{n \to \infty} \frac{tan^{-1} n}{n} = 0$

Work Step by Step

$\lim\limits_{n \to \infty} \frac{tan^{-1} n}{n} = \frac{tan^{-1}\infty}{\infty} = \frac{\frac{\pi}{2}}{\infty} = 0$ Note: $\lim\limits_{n \to \infty} tan^{-1} n = \frac{\pi}{2}$
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