Calculus: Early Transcendentals (2nd Edition)

$\lim\limits_{n \to \infty} \frac{tan^{-1} n}{n} = 0$
$\lim\limits_{n \to \infty} \frac{tan^{-1} n}{n} = \frac{tan^{-1}\infty}{\infty} = \frac{\frac{\pi}{2}}{\infty} = 0$ Note: $\lim\limits_{n \to \infty} tan^{-1} n = \frac{\pi}{2}$