Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 33

Answer

$4(3y^2+4y-2)$

Work Step by Step

Factoring the $GCF= 4 ,$ the given expression, $ 12y^2+16y-8 ,$ is equivalent to \begin{array}{l}\require{cancel} 4 \left( \dfrac{12y^2}{4}+\dfrac{16y}{4}-\dfrac{8}{4} \right) \\\\= 4(3y^2+4y-2) .\end{array}
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