Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 86

Answer

$(x+a)(x+b)$

Work Step by Step

Using factoring by grouping, the given expression, $ x^2+ax+bx+ab ,$ is equivalent to \begin{array}{l}\require{cancel} (x^2+ax)+(bx+ab) \\\\= x(x+a)+b(x+a) \\\\= (x+a)(x+b) .\end{array}
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