Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 14

Answer

$9(x+1)$

Work Step by Step

Factoring the $GCF= 9 ,$ the given expression, $ 9x+9 ,$ is equivalent to \begin{array}{l}\require{cancel} 9 \left( \dfrac{9x}{9}+\dfrac{9}{9} \right) \\\\= 9(x+1) .\end{array}
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