Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set - Page 427: 45

$10xy(3xy^2-y+2)$

Factoring the $GCF= 10xy ,$ the given expression, $ 30x^2y^3-10xy^2+20xy ,$ is equivalent to \begin{array}{l}\require{cancel} 2xy \left( \dfrac{30x^2y^3}{10xy}-\dfrac{10xy^2}{10xy}+\dfrac{20xy}{10xy} \right) \\\\= 10xy(3xy^2-y+2) .\end{array}