Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 23

Answer

$6(3y^2+2)$

Work Step by Step

Factoring the $GCF= 6 ,$ the given expression, $ 18y^2+12 ,$ is equivalent to \begin{array}{l}\require{cancel} 6 \left( \dfrac{18y^2}{6}+\dfrac{12}{6} \right) \\\\= 6(3y^2+2) .\end{array}
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