Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 47

Answer

$8x^2y(4xy-3x-2)$

Work Step by Step

Factoring the $GCF= 8x^2y ,$ the given expression, $ 32x^3y^2-24x^3y-16x^2y ,$ is equivalent to \begin{array}{l}\require{cancel} 8x^2y \left( \dfrac{32x^3y^2}{8x^2y}-\dfrac{24x^3y}{8x^2y}-\dfrac{16x^2y}{8x^2y} \right) \\\\= 8x^2y(4xy-3x-2) .\end{array}
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