Introductory Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-805-X
ISBN 13: 978-0-13417-805-9

Chapter 6 - Section 6.1 - The Greatest Common Factor and Factoring by Grouping - Exercise Set: 76

Answer

$(x+6)(x^2-2)$

Work Step by Step

Using factoring by grouping, the given expression, $ x^3+6x^2-2x-12 ,$ is equivalent to \begin{array}{l}\require{cancel} (x^3+6x^2)-(2x+12) \\\\= x^2(x+6)-2(x+6) \\\\= (x+6)(x^2-2) .\end{array}
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.