Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 372: 48

Answer

$(x-6)(x+1)(x-1)$

Work Step by Step

The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$. Hence here: $x^3-6x^2-x+6=x^2(x-6)-1(x-6)=(x-6)(x^2-1)=(x-6)(x^2-1^2)=(x-6)(x+1)(x-1)$
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