Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 372: 94

Answer

$(2x+y)(x^2+xy+y^2)$

Work Step by Step

The formula for factoring the sum of two cubes is: $A^3+B^3=(A+B)(A^2-AB+B^2)$. The formula for factoring the difference of two cubes is: $A^3-B^3=(A-B)(A^2+AB+B^2)$. Hence here: $x^3+(x+y)^3=\\=(x+x+y)((x^2-x\cdot(x+y)+(x+y)^2)\\=(2x+y)(x^2-x^2-xy+x^2+2xy+y^2)\\=(2x+y)(x^2+xy+y^2)$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.