Answer
$(3x+8y)^2$
Work Step by Step
The square of a binomial sum is: $(A+B)^2=A^2+2AB+B^2$.
The square of a binomial difference is: $(A-B)^2=A^2-2AB+B^2$.
Hence here: $9x^2+48xy+64y^2=(3x)^2+2\cdot3y\cdot8y+(8y)^2=(3x+8y)^2$
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