Answer
$(x-3)(x^2+3x+9)$
Work Step by Step
The given binomial can be written as:
$x^3-3^3$
This binomial is a difference of two cubes.
RECALL:
$a^3-b^3=(a-b)(a^2+ab+b^2)$
Factor the difference of two cubes using the formula above with $a=x$ and $b=3$ to obtain:
$=(x-3)(x^2+x(3)+3^2)
\\=(x-3)(x^2+3x+9)$
