Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 77

Answer

$(x-3)(x^2+3x+9)$

Work Step by Step

The given binomial can be written as: $x^3-3^3$ This binomial is a difference of two cubes. RECALL: $a^3-b^3=(a-b)(a^2+ab+b^2)$ Factor the difference of two cubes using the formula above with $a=x$ and $b=3$ to obtain: $=(x-3)(x^2+x(3)+3^2) \\=(x-3)(x^2+3x+9)$
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