Answer
$(x-7)(x+1)(x-1)$
Work Step by Step
The product of a binomial sum and a binomial difference is: $(A+B)(A-B)=A^2-B^2$.
Hence here: $x^3-7x^2-x+7=x^2(x-7)-1(x-7)=(x-7)(x^2-1)=(x-7)(x^2-1^2)=(x-7)(x+1)(x-1)$
Intermediate Algebra for College Students (7th Edition)
by Blitzer, Robert F.
Published by
Pearson
ISBN 10:
0-13417-894-7
ISBN 13:
978-0-13417-894-3
Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set - Page 372: 47
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