Intermediate Algebra for College Students (7th Edition)

Published by Pearson
ISBN 10: 0-13417-894-7
ISBN 13: 978-0-13417-894-3

Chapter 5 - Section 5.5 - Factoring Special Forms - Exercise Set: 75

Answer

$(x+4)(x^2-4x+16)$

Work Step by Step

The given binomial can be written as: $x^3+4^3$ This binomial is a sum of two cubes. RECALL: $a^3+b^3=(a+b)(a^2-ab+b^2)$ Factor the sum of two cubes using the formula above with $a=x$ and $b=4$ to obtain: $=(x+4)(x^2-x(4)+4^2) \\=(x+4)(x^2-4x+16)$
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