Chapter 9 - Section 9.1 - The Algebra of Functions; Composite Functions - Exercise Set - Page 540: 4

$(f+g)(x)=x^2+3x-2$ $(f−g)(x)=x^2-3x-2$ $(f×g)(x)=3x^3-6x$ $(\frac{f}{g})(x)=\frac{x^2-2}{3x}$

If $f(x)=x^2-2$ and $g(x)=3x$, then $(f+g)(x)=f(x)+g(x)=x^2-2+3x=x^2+3x-2$ $(f−g)(x)=f(x)−g(x)=x^2-2-3x=x^2-3x-2$ $(f×g)(x)=f(x)×g(x)=(x^2-2)×(3x)=3x^3-6x$ $(\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x^2-2}{3x}$