Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.1 - The Algebra of Functions; Composite Functions - Exercise Set - Page 540: 10

Answer

$3\sqrt2$

Work Step by Step

h of f(-2) means $h(f(-2))$ first find $f(-2)$: $f(-2) = (-2)^2-6(-2)+2=4+12+2=18$ then find $h(18)$: $h(18) = \sqrt{18}=\sqrt{9}\times\sqrt{2}=3\sqrt2$
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