Answer
$f(x)=\dfrac{1}{x}$ and $g(x)=x+10$
Work Step by Step
$h(x)=\dfrac{1}{x+10}$
For $h(x)$ to be $(f\circ g)(x)$, $f(x)$ must be $\dfrac{1}{x}$ and $g(x)$ must be $x+10$.
This can be verified by substituting $x$ by $g(x)$ in $f(x)$ and checking if it matches the original function $h(x)$.
