Answer
$f(g(x))=7\sqrt[3] x-1$
$g(f(x))=\sqrt[3] {7x-1}$
Work Step by Step
f of g(x) means $f(g(x))$
$g(x)$ is given as $\sqrt[3] x$
Therefore $f(g(x))=7\sqrt[3] x-1$
g of f(x) means $g(f(x))$
$f(x)$ is given as $7x-1$
Therefore $g(f(x))=\sqrt[3] {7x-1}$
