Answer
$(f+g)(x)=6x+2$
$(f−g)(x)=−4x+6$
$(f×g)(x)=5x^2+18x-8$
$(\frac{f}{g})(x)=\frac{x+4}{5x-2}$
Work Step by Step
If $f(x)=x+4$ and $g(x)=5x-2$, then
$(f+g)(x)=f(x)+g(x)=x+4+5x-2=6x+2$
$(f−g)(x)=f(x)−g(x)=x+4−(5x-2)=−4x+6$
$(f×g)(x)=f(x)×g(x)=(x+4)×(5x-2)=5x^2+20x-2x-8=5x^2+18x-8$
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x+4}{5x-2}$
