Answer
$f(g(x))=3x+11$
$g(f(x))=3x+31$
Work Step by Step
f of g(x) means $f(g(x))$
$g(x)$ is given as $3x+1$
Therefore $f(g(x))=(3x+1)+10=3x+11$
g of f(x) means $g(f(x))$
$f(x)$ is given as $x+10$
Therefore $g(f(x))=3(x+10)+1=3x+30+1=3x+31$