Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 9 - Section 9.1 - The Algebra of Functions; Composite Functions - Exercise Set - Page 540: 18

Answer

$f(g(x))=3x+11$ $g(f(x))=3x+31$

Work Step by Step

f of g(x) means $f(g(x))$ $g(x)$ is given as $3x+1$ Therefore $f(g(x))=(3x+1)+10=3x+11$ g of f(x) means $g(f(x))$ $f(x)$ is given as $x+10$ Therefore $g(f(x))=3(x+10)+1=3x+30+1=3x+31$
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