Answer
$(f+g)(x)=3x-6$
$(f-g)(x)=-x-8$
$(f\times g)(x)=2x^2-13x-7$
$(\frac{f}{g})(x)=\frac{x-7}{2x+1}$
Work Step by Step
If $f(x)=x-7$ and $g(x)=2x+1$, then
$(f+g)(x)=f(x)+g(x)=x-7+2x+1=3x-6$
$(f-g)(x)=f(x)-g(x)=x-7-(2x+1)-x-8$
$(f\times g)(x)=f(x)\times g(x)=(x-7)\times(2x+1) =2x^2-14x+x-7=2x^2-13x-7$
$(\frac{f}{g})(x)=\frac{f(x)}{g(x)}=\frac{x-7}{2x+1}$
