Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 12

Answer

$x=-2$

Work Step by Step

$\sqrt[3] (4x)=-2$ Cube both sides of the equation. $(\sqrt[3] (4x))^{3}=(-2)^{3}$ $4x=-8$ Divide both sides by 4. $x=-2$
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