Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set - Page 453: 32

Answer

$x=9$

Work Step by Step

Squaring both sides of the given equation, $ \sqrt{3x+9}=6 ,$ then the solution/s is/are \begin{array}{l}\require{cancel} 3x+9=36 \\\\ 3x=36-9 \\\\ 3x=27 \\\\ x=\dfrac{27}{3} \\\\ x=9 .\end{array} Upon checking, $ x=9 $ satisfies the original equation.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.