Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 11

Answer

$x=-\frac{9}{2}$

Work Step by Step

$\sqrt[3] (6x)=-3$ Cube both sides of the equation. $(\sqrt[3] (6x))^{3}=(-3)^{3}$ $6x=-27$ Divide both sides by 6. $x=-\frac{27}{6}=-\frac{9}{2}$
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