## Intermediate Algebra (6th Edition)

$x=6$
$\sqrt (2x-3)-2=1$ Add 2 to both sides of the equation. $\sqrt (2x-3)=3$ Square both sides. $(\sqrt (2x-3))^{2}=3^{2}$ $2x-3=9$ Add 3 to both sides. $2x=12$ Divide both sides by 2. $x=6$