Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 14

Answer

$x=35$

Work Step by Step

$\sqrt[3] (2x-6)-4=0$ Add 4 to both sides of the equation. $\sqrt[3] (2x-6)=4$ Cube both sides. $(\sqrt[3] (2x-6))^{3}=4^{3}$ $2x-6=64$ Add 6 to both sides. $2x=70$ Divide both sides by 2. $x=35$
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