Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 8

Answer

$x=4$

Work Step by Step

$\sqrt (x-3)-1=0$ Add 1 to both sides of the equation. $\sqrt (x-3)=1$ Square both sides. $(\sqrt (x-3))^{2}=1^{2}$ $x-3=1$ Add 3 to both sides. $x=4$
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