Intermediate Algebra (6th Edition)

Published by Pearson
ISBN 10: 0321785045
ISBN 13: 978-0-32178-504-6

Chapter 7 - Section 7.6 - Radical Equations and Problem Solving - Exercise Set: 4

Answer

$x=24$

Work Step by Step

$\sqrt (x+1)=5$ Square both sides of the equation. $(\sqrt (x+1))^{2}=5^{2}$ $x+1=25$ Subtract 1 from both sides. $x=24$
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