Answer
$3z(z-1)(z^2+z+1)$
Work Step by Step
Factoring the $GCF=
3z^2
,$ the given expression, $
3z^5-3z^2
,$ is equivalent to
\begin{array}{l}
3z^2(z^3-1)
.\end{array}
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the expression, $
3z^2(z^3-1)
,$ is
\begin{array}{l}
3z(z-1)[ (z)^2-(z)(-1)+(-1)^2]
\\\\=
3z(z-1)(z^2+z+1)
.\end{array}