## Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

$(x-0.1)(x^2+0.1x+0.01)$
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $x^3-0.001 ,$ is \begin{array}{l} (x-0.1)[ (x)^2-(x)(-0.1)+(-0.1)^2] \\\\= (x-0.1)(x^2+0.1x+0.01) .\end{array}