Chapter 5 - Polynomials and Factoring - 5.5 Factoring Sums or Differences of Cubes - 5.5 Exercise Set - Page 338: 15

$(t-10)(t^2+10t+100)$

Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $ t^3-1000 ,$ is \begin{array}{l} (t-10)[(t)^2-(t)(-10)+(-10)^2] \\\\= (t-10)(t^2+10t+100) .\end{array}