Answer
$5(x-2z)(x^2+2xz+4z^2)$
Work Step by Step
Factoring the $GCF=
5
,$ the given expression, $
5x^3-40z^3
,$ is equivalent to
\begin{array}{l}
5(x^3-8z^3)
.\end{array}
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the expression, $
5(x^3-8z^3)
,$ is
\begin{array}{l}
5(x-2z)[ (x)^2-(x)(-2z)+(-2z)^2]
\\\\=
5(x-2z)(x^2+2xz+4z^2)
.\end{array}