Chapter 5 - Polynomials and Factoring - 5.5 Factoring Sums or Differences of Cubes - 5.5 Exercise Set - Page 338: 19

$(4-5x)(16+20x+25x^2)$

Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $ 64-125x^3 ,$ is \begin{array}{l} (4-5x)[(4)^2-(4)(-5x)+(5x)^2] \\\\= (4-5x)(16+20x+25x^2) .\end{array}