Answer
$(x+2)(x^2-2x+4)$
Work Step by Step
Using $a^3+b^3=(a+b)(a^2-ab+b^2)$ or the factoring of 2 cubes, the factored form of the given expression, $
x^3+8
,$ is
\begin{array}{l}
(x+2)[(x)^2-(x)(2)+(2)^2]
\\\\=
(x+2)(x^2-2x+4)
.\end{array}