Answer
$-\dfrac{4y^{11}}{x^{3}}$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{12x^{-2}y^4}{-3xy^{-7}}
$, is equivalent to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{-3}\cdot(-4)x^{-2-1}y^{4-(-7)}}{\cancel{-3}xy^{-7}}
\\\\=
-4x^{-3}y^{11}
\\\\=
-\dfrac{4y^{11}}{x^{3}}
.\end{array}