Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set: 82

Answer

$\dfrac{32d^{15}}{a^{10}b^5}$

Work Step by Step

Using the laws of exponents, the given expression, $ \left( \dfrac{a^2b}{2d^3} \right)^{-5} $, is equivalent to \begin{array}{l}\require{cancel} \left( \dfrac{2d^3}{a^2b} \right)^{5} \\\\= \dfrac{2^5d^{3(5)}}{a^{2(5)}b^5} \\\\= \dfrac{32d^{15}}{a^{10}b^5} .\end{array}
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