Chapter 4 - Polynomials - 4.2 Negative Exponents and Scientific Notations - 4.2 Exercise Set - Page 244: 74

$\dfrac{y^{12}z^{6}}{8}$

Using the laws of exponents, the given expression, $ (2y^{-4}z^{-2})^{-3} $, is equivalent to \begin{array}{l}\require{cancel} 2^{-3}y^{-4(-3)}z^{-2(-3)} \\\\= 2^{-3}y^{12}z^{6} \\\\= \dfrac{y^{12}z^{6}}{2^{3}} \\\\= \dfrac{y^{12}z^{6}}{8} .\end{array}