Answer
Option (c)
Work Step by Step
RECALL:
A negative exponent means reciprocal.
Thus, $a^{-m} = \frac{1}{a^m}=(\frac{1}{a})^m$.
Using the rule above gives:
$(\frac{x^3}{y^2})^{-2}=(\frac{y^2}{x^3})^2$
Simplify using the rule $(a^m)^n=a^{mn}$ to obtain:
$=\dfrac{y^{2(2)}}{x^{3(2)}}
\\=\dfrac{y^4}{x^6}$
Thus, the answer is Option (c).