Answer
$1$
Work Step by Step
Using the laws of exponents, the given expression, $
\dfrac{t^{-7}}{t^{-7}}
$, is equivalent to
\begin{array}{l}\require{cancel}
t^{-7-(-7)}
\\\\=
t^{-7+7}
\\\\=
t^{0}
\\\\=
1
.\end{array}
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