Answer
$\dfrac{1}{x^{12}}$
Work Step by Step
Using the laws of exponents, the given expression, $
x^{-3}\cdot x^{-9}
$, is equivalent to
\begin{array}{l}
x^{-3+(-9)}
\\\\=
x^{-3-9}
\\\\=
x^{-12}
\\\\=
\dfrac{1}{x^{12}}
.\end{array}
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