Answer
$\dfrac{1}{m^{7}n^{7}}$
Work Step by Step
Using the laws of exponents, the given expression, $
(mn)^{-7}
$, is equivalent to
\begin{array}{l}
m^{-7}n^{-7}
\\\\=
\dfrac{1}{m^{7}n^{7}}
.\end{array}
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