Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set - Page 236: 95

$n\lt\dfrac{16}{3}$

The solution to the given expression, $ 8-2(n-7)\gt9-(3-n) $, is \begin{array}{l}\require{cancel} 8-2(n)-2(-7)\gt9-3+n \\\\ 8-2n+14\gt9-3+n \\\\ -2n-n\gt9-3-8-14 \\\\ -3n\gt-16 \\\\ n\lt\dfrac{-16}{-3} \\\\ n\lt\dfrac{16}{3} .\end{array}