Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 69

Answer

$a^{14}b^{7}$

Work Step by Step

Using $(ab)^x=a^xb^x$, then the expression, $ (a^2b)^{7} $, simplifies to \begin{array}{l}\require{cancel} a^{2(7)}b^{7} \\\\= a^{14}b^{7} .\end{array}
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