Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 73

Answer

$24x^{19}$

Work Step by Step

Using $(ab)^x=a^xb^x$, then the expression, $ (2x^5)^3(3x^4) $, simplifies to \begin{array}{l}\require{cancel} (2^3x^{5(3)})(3x^4) \\\\= (8x^{15})(3x^4) .\end{array} Using $a^x\cdot a^y=a^{x+y}$, then given expression, $ (8x^{15})(3x^4) $, simplifies to \begin{array}{l}\require{cancel} 8\cdot3x^{15+4} \\\\= 24x^{19} .\end{array}
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