Answer
$t^{7}$
Work Step by Step
Using $\dfrac{a^x}{a^y}=a^{x-y}$, then the expression, $
\dfrac{t^8}{t}
$, simplifies to
\begin{array}{l}\require{cancel}
t^{8-1}
\\\\=
t^{7}
.\end{array}
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