Elementary and Intermediate Algebra: Concepts & Applications (6th Edition)

Published by Pearson
ISBN 10: 0-32184-874-8
ISBN 13: 978-0-32184-874-1

Chapter 4 - Polynomials - 4.1 Exponents and Their Properties - 4.1 Exercise Set: 48

Answer

$a^{8}b^{12}$

Work Step by Step

Using $\dfrac{a^x}{a^y}=a^{x-y}$, then the expression, $ \dfrac{a^{10}b^{12}}{a^2b^0} $, simplifies to \begin{array}{l}\require{cancel} a^{10-2}b^{12-0} \\\\= a^{8}b^{12} .\end{array}
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