Answer
$3r^{8}s^{6}$
Work Step by Step
Using $\dfrac{a^x}{a^y}=a^{x-y}$, then the expression, $
\dfrac{12r^{10}s^7}{4r^2s}
$, simplifies to
\begin{array}{l}\require{cancel}
\dfrac{\cancel{4}\cdot3r^{10-2}s^{7-1}}{\cancel{4}}
\\\\=
3r^{8}s^{6}
.\end{array}