Answer
$1$
Work Step by Step
Using $\dfrac{a^x}{a^y}=a^{x-y}$, then the expression, $
\dfrac{(x+y)^8}{(x+y)^8}
$, simplifies to
\begin{array}{l}\require{cancel}
(x+y)^{8-8}
\\\\=
(x+y)^{0}
\\\\=
1
.\end{array}
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